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1、互为相反数即和为0， ∴根号a-4 + |b-9| = 0 又根号a-4 >= 0 |b-9| >= 0 ∴根号a-4 = 0，|b-9| = 0 即a-4 = 0。

2、b-9 = 0 ∴a = 4，b = 9 根号ab = 根号36 = 6 （2x²-4x+2）+ 根号(x+2+2y-1) = 0 2(x-1)² + 根号(x+2+2y-1) = 0 ∵2(x-1)² >= 0 根号(x+2+2y-1) >= 0 ∴2(x-1)² = 0 根号(x+2+2y-1) = 0 即x-1 = 0 x+2+2y-1 = 0 解得x = 1，y = -1 ∴xy = -1。

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